interleaving dictionary values

[Noah Rawlins]

j1o1h1n at gmail.com wrote:

> filter(None, - my brain parses that automatically now.  This is not so
> bad.  Flatten is snitched from ASPN/Cookbook/Python/Recipe/363051,
> thank you Jordan Callicoat, Mike C. Fletcher:
> 
> def flatten(l, ltypes=(list, tuple)):
>     i = 0
>     while (i < len(l)):
>        while (isinstance(l[i], ltypes)):
>            l[i:i+1] = list(l[i])
>        i += 1
>     return l
> 

On a side note, that version of flatten doesn't handle an empty list as 
the last element of a list...

 >>> flatten([1, 2, 3, []])
Traceback (most recent call last):
   File "<stdin>", line 1, in <module>
   File "<stdin>", line 4, in flatten
IndexError: list index out of range

You need a try: in there or something...

def flatten(l, ltypes=(list, tuple)):
     i = 0
     while(i < len(l)):
         try:
             while(isinstance(l[i], ltypes)):
                 l[i:i+1] = list(l[i])
             i += 1
         except IndexError:
            pass
     return l

noah