Computing FFT with Python NumPy 1.0
Robert Kern
robert.kern at gmail.com
Wed Nov 1 19:18:31 EST 2006
mcdurr at gmail.com wrote:
> I recently installed Python 2.5 on Windows and also installed numpy
> 1.0.
You will want to ask numpy questions on the numpy mailing list.
http://www.scipy.org/Mailing_Lists
> I'd like to compute an FFT on an array of numbers but I can't
> seem to access the FFT function. I'm fairly new to Python (obviously)
> and I can't seem to find documentation to match my distribution of
> numpy and I can't figure out how to access the FFT function.
>
> Python 2.5 (r25:51908, Sep 19 2006, 09:52:17) [MSC v.1310 32 bit
> (Intel)] on win32
> Type "copyright", "credits" or "license()" for more information.
>
> IDLE 1.2
>>>> from numpy import *
>>>> a=array((1,2,3,2,1,2,3,2,1))
>>>> fft(a)
>
> Traceback (most recent call last):
> File "<pyshell#2>", line 1, in <module>
> fft(a)
> TypeError: 'module' object is not callable
All of the fft functions are in the numpy.fft module.
>>> from numpy import *
>>> a=array((1,2,3,2,1,2,3,2,1))
>>> fft.fft(a)
array([ 1.70000000e+01+0.j , -1.15270364e+00-0.41954982j,
-3.37938524e+00-2.83564091j, 5.00000000e-01+0.8660254j ,
3.20888862e-02+0.18198512j, 3.20888862e-02-0.18198512j,
5.00000000e-01-0.8660254j , -3.37938524e+00+2.83564091j,
-1.15270364e+00+0.41954982j])
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is made terrible by our own mad attempt to interpret it as though it had
an underlying truth."
-- Umberto Eco
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