forwarding *arg parameter
Tuomas
tuomas.vesterinen at pp.inet.fi
Sun Nov 5 14:35:58 EST 2006
Stargaming wrote:
> Either you take one of the snippets here:
> http://aspn.activestate.com/ASPN/search?query=flatten§ion=PYTHONCKBK&type=Subsection
>
> or just use arg[0] clever (as mentioned a few times in this thread).
Thanks. My solution became:
>>> def flattern(arg):
... result = []
... for item in arg:
... if isinstance(item, (list, tuple)):
... result.extend(flattern(item))
... else:
... result.append(item)
... return tuple(result)
...
>>> def g(*arg):
... arg = flattern(arg)
... return arg
...
>>> def f(*arg):
... return g(arg)
...
>>> f('foo', 'bar')
('foo', 'bar')
TV
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