list*list

[bearophileHUGS at lycos.com]

Ziga Seilnach:
>c = map(operator.mul, a, b)

Usually I like map a lot, but this time for me the l.c. version is a
bit simpler to understand (even if it's longer, and maybe slower too):

>>> from operator import mul
>>> from itertools import izip
>>> a = [1, 2, 3]
>>> b = [4, 5, 6]
>>> map(mul, a, b)
[4, 10, 18]
>>> [arow * brow for arow, brow in izip(a, b)]
[4, 10, 18]

Bye,
bearophile