How to pass variables between scripts?

[Gross, Dorit (SDRN)]

Marcelo, thank you very much for your help!!! The script is running nicely
now and I can pass the variables easily between the scripts.

If someone else followed this topic ... a short note at the end. 
It seems that with the 'globvars' also the modules used by 'second.py' have
to be passed. Somehow the modules defined in 'second.py' itself are not
available when 'second.py' is called from an external script. So adding
following line to the external script solves the problem:

globvars = { 'os' : __import__('os') }

Many thanks again,
Dorit


> -----Original Message-----
> From: python-list-bounces+dorit.gross=fao.org at python.org 
> [mailto:python-list-bounces+dorit.gross=fao.org at python.org] 
> On Behalf Of Marcelo Ramos
> Sent: 16 May 2006 19:51
> To: python-list at python.org
> Subject: Re: How to pass variables between scripts?
> 
> 
> Gross, Dorit (SDRN) escribió:
> >>> #! /usr/local/bin/python
> >>> # test_exec.py
> >>>
> >>> import os, sys, glob
> >>>
> >>> fileList = glob.glob('/data/*.ZIP')
> >>>
> >>> for f in fileList:
> >>> 	try: 
> >>> 		globvars = {'infile' : f}
> >>> 		locvars = {}
> >>> 		execfile('/scripts/second.py', globvars(), locvars)
> >>> 	except IOError:
> >>> 		exit(0)
> >>> 	print locvars
> >>>
> >>>
> >>>       
> >> You are calling the dictionary globvars as a function then 
> the error.
> >> The fixed line is:
> >>
> >> execfile('/scripts/second.py', globvars, locvars)
> >>
> >>
> >>
> >> What you want is the function globals().
> >> Try putting this line in second.py:
> >>
> >> print globals()['infile']
> >>
> >> Using the dictionary returned by globals() you can make 
> second.py to
> >> read the contents of testexec.py's globvars dictionary.
> >> locvars is populated with the local variables of second.py 
> >> and that is 
> >> what you want.
> >>
> >>     
> >
> > Marcelo, thank you! Passing the variables with dictonaries and 
> > function
> > globals() works fine if no other functions are defined in 
> 'second.py'. Now
> > 'second.py' contains further functions and a "if __name__ = 
> __main__"
> > statement and in this case it seems that 'second.py' is not 
> fully executed
> > from 'test_exec.py'. For the sole purpose of testing, 
> 'second.py' looks like
> > this at the moment:
> >
> > #! /usr/local/bin/python
> > # second.py
> >
> > import os, sys
> >
> > global zipfile
> > print 'Read from globals: ' + globals()['infile']
> > zipfile = globals()['infile']
> > print 'Read from zipfile: ' + zipfile
> >
> > if __name__ == '__main__':
> >
> > 	print 'Hello'
> > 	print globals()['infile']
> > 	print zipfile
> >
> > 	
> > Calling test_exec.py results into this output:
> >
> >  ./test_exec.py
> > Read from globals: /data/S0012230_0010.ZIP
> > Read from zipfile: /data/S0012230_0010.ZIP
> >
> >
> > It seems that the commands within the main are not executed when 
> > calling test_exec.py!?! Is there a way to make it running?
> >
> > Regards and thank you again,
> > Dorit
> >
> >
> >   
> If you print __name__ in second.py its value is 
> '__builtin__', because 
> of that your "main" doesn't execute.
> Try adding this to test_exec.py before the execfile() call:
> 
> globvars[ '__name__' ] = '__main__'
> 
> It looks like a ad hoc fix but i couldn't find any doc about 
> the change 
> of __name__ to 'builtin' of a python script being run
> from another with execfile().
> 
> Regards.
> 
> -- 
> Marcelo Ramos
> Fedora Core 5 | 2.6.16
> Socio UYLUG Nro 125
> 
> -- 
> http://mail.python.org/mailman/listinfo/python-list
>