Separating elements from a list according to preceding element
Michael Spencer
mahs at telcopartners.com
Sun Mar 5 18:48:04 EST 2006
Rob Cowie wrote:
> I'm having a bit of trouble with this so any help would be gratefully
> recieved...
>
> After splitting up a url I have a string of the form
> 'tag1+tag2+tag3-tag4', or '-tag1-tag2' etc. The first tag will only be
> preceeded by an operator if it is a '-', if it is preceded by nothing,
> '+' is to be assumed.
>
> Using re.split, I can generate a list that looks thus:
> ['tag1', '+', 'tag2', '+', 'tag3', '-', 'tag4']
>
> I wish to derive two lists - each containing either tags to be
> included, or tags to be excluded. My idea was to take an element,
> examine what element precedes it and accordingly, insert it into the
> relevant list. However, I have not been successful.
>
> Is there a better way that I have not considered? If this method is
> suitable, how might I implement it?
>
> Thanks all,
>
> Rob Cowie
>
Since you're already using a regexp, why not modify it to group the operators
with their tags? :
>>> import re
>>> source = "tag1+tag2+tag3-tag4"
...
>>> tagfinder = re.compile("([+-]?)(\w+)")
...
>>> include = []
>>> exclude = []
...
>>> for op, tag in tagfinder.findall(source):
... if op == "-":
... exclude.append(tag)
... else:
... include.append(tag)
...
>>> include
['tag1', 'tag2', 'tag3']
>>> exclude
['tag4']
>>>
(Example assumes that a tag can be matched by \w+ and that there
is no space between the operators and their tags)
Michael
More information about the Python-list
mailing list