object's list index
Sebastjan Trepca
trepca at gmail.com
Fri Mar 3 07:30:25 EST 2006
Um, what about:
for oindex in xrange(len(list)):
object = list[oindex]
print oindex
You can't create a generic function for this.
Sebastjan
On 3/3/06, William Meyer <wmmeyer at gmail.com> wrote:
> hi,
>
> I need to get the index of an object in a list. I know that no two objects
> in the list are the same, but objects might evaluate as equal. for example
>
> list = [obj1, obj2, obj3, obj4, obj5]
> for object in list:
> objectIndex = list.index(object)
> print objectIndex
>
> prints 0, 1, 2, 3, 2 instead of 0, 1, 2, 3, 4 because obj3 == obj5. I could loop
> through the list a second time comparing id()'s
>
> for object in list:
> objectIndex = 0
> for i in list:
> if id(object) == id(i):
> break
> objectIndex += 1
> print objectIndex
>
> but that seems like a real ugly pain. Somewhere, someplace python is keeping
> track of the current index in list, does anyone know how to access it? Or have
> any other suggestions?
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
More information about the Python-list
mailing list