Attaching files in windows using Python.

Roger Upole rupole at hotmail.com
Sat Mar 11 16:35:42 EST 2006


You might want to try using win32gui.GetOpenFileNameW.
It uses keyword arguments and doesn't require that you
build a struct yourself:

win32gui.GetOpenFileNameW(File='myfile.txt', Filter='Texts and scripts\0*.txt;*.py\0Py stuff\0*.py\0')

    Roger


"sri2097" <srikar2097 at gmail.com> wrote in message news:1141752053.029483.42540 at p10g2000cwp.googlegroups.com...
> Hi all,
> I have got this far till now -
>
> import win32gui, struct, array, string
>
> OFN_ALLOWMULTISELECT=0x00000200
> OFN_EXPLORER=0x00080000
>
> def arrayToStrings(resultArray):
>    """return list-of-strings corresponding to a char array,
>       where each string is terminated by \000, and the whole
>       list by two adjacent \000 bytes
>    """
>    astr=resultArray.tostring()
>    manyStrings=[]
>    # perhaps a loop of string.split would be faster...
>    while len(astr) and astr[0]!='\000':
>        i=astr.index('\000')
>        manyStrings.append(astr[:i])
>        astr=astr[i+1:]
>    return manyStrings
>
> def szFrom(anarray):
>    """return the string-pointer (sz) corresponding to a char
>       array, 0 (null pointer) if no array
>    """
>    if anarray: return anarray.buffer_info()[0]
>    else: return 0
>
> def arrayFrom(astring,additional=0):
>    """return a char array built from a string, plus 0
>       or more \000 bytes as filler
>    """
>    if not astring: astring=''
>    return array.array('c',astring+additional*'\000')
>
> def arrayMulti(stringlist):
>    """return a char array built from many strings, each
>       separated by a \000 byte, and two \000's at the end
>    """
>    return arrayFrom(string.join(stringlist,'\000'),2)
>
> def buildOfn(resultarray,filters=None,initdir=None,title=None,
>             multisel=1,oldlook=0):
>    """build an OPENFILENAME struct as a string, with several
>       options and a given result-array for the string[s] that
>       will result from the GetOpenFileName call
>    """
>    flags=OFN_EXPLORER
>    if multisel: flags=flags|OFN_ALLOWMULTISELECT
>    if oldlook: flags=flags&~OFN_EXPLORER
>    szfile,maxfile=resultarray.buffer_info()
>    szfilter=szFrom(filters)
>    szinitdir=szFrom(initdir)
>    sztitle=szFrom(title)
>    return struct.pack(
>        "3i2P2iPiPi2PI2hPi2P",
>        76, 0, 0,           # size, owner-hwnd, hinstance
>        szfilter, 0, 0, 0,  # filter, custom-filter,
> max-cust-filter,filter-index
>        szfile, maxfile,    # file, max-file
>        0, 0,               # file-title, max-file-title
>        szinitdir, sztitle, # initial-dir, dialog-title
>        flags, 0, 0,        # flags, file-offset, file-extension
>        0,                  # def-ext
>        0, 0, 0)            # cust-data, func-hook, template-name
>
> def openNames(forsave=0,filters=None,initdir=None,title=None,
>              initfile=None,multisel=1,oldlook=0):
>    """return a list of filenames for open or save, given
>       interactively by the user through a common-dialog; if
>       more than 1 string is returned, the first is the directory,
>       followed by the filenames.
>    """
>    resultBuffer=arrayFrom(initfile,8192)
>    title=arrayFrom(title)
>    initdir=arrayFrom(initdir)
>    filters=arrayMulti(filters)
>    ofn=buildOfn(resultBuffer,filters,initdir,title,multisel,oldlook)
>    if forsave: isok=win32gui.GetSaveFileName(ofn)
>    else: isok=win32gui.GetOpenFileName(ofn)
>    if not isok: return []
>    return arrayToStrings(resultBuffer)
>
> def _test():
>    return openNames(
>        filters=('Texts and scripts','*.txt;*.py','Py stuff','*.py*')
>    )
>
> if __name__=='__main__':
>    print _test()
>
> But hear the Dialogue_box stops and waits for the user to select a
> file. But Since I have the entire path of the file, How do I pass it to
> the file name to populate the box automatically instead of the user
> manually selecting a file.
>
> Any further help will be appreciated.
> 



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