What is Expressiveness in a Computer Language

[Chris Smith]

Pascal Costanza <pc at p-cos.net> wrote:
> You can ignore the #'. In Scheme this as follows:
> 
> (define blackhole (argument)
>    blackhole)
> 
> It just means that the function blackhole returns the function blackhole.

So, in other words, it's equivalent to (Y (\fa.f)) in lambda calculus, 
where \ is lambda, and Y is the fixed point combinator?

-- 
Chris Smith - Lead Software Developer / Technical Trainer
MindIQ Corporation