How to control permission of file?

Schüle Daniel uval at rz.uni-karlsruhe.de
Fri Jun 30 18:06:38 EDT 2006


> True, but I don't see what it has to do with my question.

my mistake, I misunderstood your question

as Sreeram said, os.open can be used


help(os.open)

Help on built-in function open:

open(...)
     open(filename, flag [, mode=0777]) -> fd

     Open a file (for low level IO).


 >>> import os
 >>> fd=os.open("secret", os.O_WRONLY|os.O_CREAT, 0400)
 >>> os.write(fd,"not for everybody")
17
 >>> os.close(fd)


ls -l secret
-r--------    1 root     root           17 2006-07-01 00:05 secret


Regards, Daniel



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