Generating all ordered substrings of a string
Gerard Flanagan
grflanagan at yahoo.co.uk
Wed Jul 12 16:30:54 EDT 2006
girish at it.usyd.edu.au wrote:
> Hi,
> I want to generate all non-empty substrings of a string of length >=2.
> Also,
> each substring is to be paired with 'string - substring' part and vice
> versa.
> Thus, ['abc'] gives me [['a', 'bc'], ['bc', 'a'], ['ab', 'c'], ['c',
> 'ab'], ['b', 'ac'], ['ac', 'b']] etc.
> Similarly, 'abcd' should give me [['a', 'bcd'], ['bcd', 'a'], ['abc',
> 'd'], ['d', 'abc'], ['b', 'acd'], ['acd', 'b'],['c', 'abd'], ['abd', 'c'],
> ['ab', 'cd'], ['cd', 'ab'], ['bc', 'ad'], ['ad', 'bc'], ['ac',
> 'bd'],['bd','ac']]
>
from a previous post
(http://groups.google.com/group/comp.lang.python/browse_frm/thread/fa40c76544b1c515/cef5b578bb00e61b?lnk=st&q=&rnum=23#cef5b578bb00e61b)
def nkRange(n,k):
m = n - k + 1
indexer = range(0, k)
vector = range(1, k+1)
last = range(m, n+1)
yield vector
while vector != last:
high_value = -1
high_index = -1
for i in indexer:
val = vector[i]
if val > high_value and val < m + i:
high_value = val
high_index = i
for j in range(k - high_index):
vector[j+high_index] = high_value + j + 1
yield vector
def kSubsets(s, k):
for vector in nkRange(len(s),k):
yield ''.join( s[i-1] for i in vector )
print list( kSubsets('abcd',2) )
['ab', 'ac', 'ad', 'bc', 'bd', 'cd']
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