How do you implement this Python idiom in C++

[alainpoint at yahoo.fr]

Hello,

I have the need to write the equivalent of Python class methods in C++.

Chuck Allison proposes the following
(http://www.artima.com/cppsource/simple.html):
#include <iostream>
using namespace std;

// A base class that provides counting
template<class T> class Counted {
  static int count;
public:
  Counted() { ++count; }
  Counted(const Counted<T>&) { ++count; }
  ~Counted() { --count; }
  static int getCount() { return count; }

};

template<class T> int Counted<T>::count = 0;

// Curious class definitions
class CountedClass : public Counted<CountedClass> {};
class CountedClass2 : public Counted<CountedClass2> {};

It apparently works but in fact it doesn't:
If you derive from such a class, you get the count of the parent class,

not of the derived class.
class CountedClass3 : public CountedClass {};

int main() {
  CountedClass a;
  cout << CountedClass::getCount() << endl;    // 1
  CountedClass b;
  cout << CountedClass::getCount() << endl;    // 2
  CountedClass3 c;
  cout << CountedClass3::getCount() << endl;   // 3 and should be 1
  cout << CountedClass::getCount() << endl;    // 3 and should be 2

}

I am no C++ expert but i guess there might be some in the Python and
C++ newsgroups. 

Alain