Built-in Exceptions - How to Find Out Possible Errno's

[Mark Peters]

A quick test:

>>> try:
	f = open("foo","r")
except IOError, error:
	print errno.errorcode[error.errno]

ENOENT

It looks to me like your if statement should be as simple as:

if error.errno == errno.ENOENT:
    print os.strerror(error.errno)

Mark