Regex help needed

[rh0dium]

Paul McGuire wrote:
> -- Paul
> (Download pyparsing at http://pyparsing.sourceforge.net.)

Done.


Hey this is pretty cool!  I have one small problem that I don't know
how to resolve.  I want the entire contents (whatever it is) of line 1
to be the ident.  Now digging into the code showed a method line,
lineno and LineStart LineEnd.  I tried to use all three but it didn't
work for a few reasons ( line = type issues, lineno - I needed the data
and could't get it to work, LineStart/End - I think it matches every
line and I need the scope to line 1 )

So here is my rendition of the code - But this is REALLY slick..

I think the problem is the parens on line one....

def main(data=None):

    LPAR = Literal("(")
    RPAR = Literal(")")

    # assume function identifiers must start with alphas, followed by
zero or more
    # alphas, numbers, or '_' - expand this defn as needed
    ident = LineStart + LineEnd

    # define a list as one or more quoted strings, inside ()'s - we'll
tackle nesting
    # in a minute
    quoteList = Group( LPAR.suppress() + OneOrMore(dblQuotedString) +
RPAR.suppress())

    # define format of a line of data - don't bother with \n's or \r's,

    # pyparsing just skips 'em
    dataFormat = ident + ( dblQuotedString | quoteList )

    return dataFormat.parseString(data)


# General run..
if __name__ == '__main__':


#     data = 'someFunction\r\n "test" "foo"\r\n'
#     data = 'someFunction\r\n "test  foo"\r\n'
    data = 'getVersion()\r\n"@(#)$CDS: icfb.exe version 5.1.0
05/22/2005 23:36 (cicln01) $"\r\n'
#     data = 'someFunction\r\n ("test" "test1" "foo aasdfasdf"\r\n
"newline" "test2")\r\n'

    foo = main(data)

    print foo