flatten a level one list

[Tim Hochberg]

Michael Spencer wrote:
>  > Robin Becker schrieb:
>  >> Is there some smart/fast way to flatten a level one list using the
>  >> latest iterator/generator idioms.
> ...
> 
> David Murmann wrote:
>  > Some functions and timings
> ...

Here's one more that's quite fast using Psyco, but only average without it.


def flatten6():
     n = min(len(xdata), len(ydata))
     result = [None] * (2*n)
     for i in xrange(n):
             result[2*i] = xdata[i]
             result[2*i+1] = ydata[i]

-tim


> 
> Here are some more timings of David's functions, and a couple of additional 
> contenders that time faster on my box  (I don't have psyco):
> 
> # From David Murman
> from itertools import izip
> 
> xdata = range(1000)
> ydata = range(1000)[::-1]
> 
> def flatten1(x, y):
>      return [i for pair in izip(x, y) for i in pair]
> 
> def flatten2(x, y):
>      return [i for pair in zip(x, y) for i in pair]
> 
> def flatten3(x, y):
>      res = []
>      for pair in izip(x, y):
>          for i in pair:
>              res.append(i)
>      return res
> 
> 
> # New attempts:
> from itertools import imap
> def flatten4(x, y):
>      l = []
>      list(imap(l.extend, izip(x, y)))
>      return l
> 
> 
> from Tkinter import _flatten
> def flatten5(x, y):
>      return list(_flatten(zip(x, y)))
> 
> flatten_funcs = [flatten1, flatten2, flatten3, flatten4, flatten5]
> 
> def testthem():
>      flatten1res = flatten_funcs[0](xdata, ydata)
>      for func in flatten_funcs:
>          assert func(xdata, ydata) == flatten1res
> 
> def timethem():
>      for func in flatten_funcs:
>          print shell.timefunc(func, xdata, ydata)
> 
>   >>> testthem()
>   >>> timethem()
>   flatten1(...)  704 iterations, 0.71msec per call
>   flatten2(...)  611 iterations, 0.82msec per call
>   flatten3(...)  344 iterations, 1.46msec per call
>   flatten4(...)  1286 iterations, 389.08usec per call
>   flatten5(...)  1219 iterations, 410.24usec per call
>   >>>
> 
> Michael
>