getting a KeyError:'href' any ideas?

[homepricemaps at gmail.com]

what is the syntax used to find a child of td?

Mike Meyer wrote:
> "homepricemaps at gmail.com" <homepricemaps at gmail.com> writes:
>
> Please use less whitespace in your posts in the future. There's really
> no need to put two blank lines between sections.
>
> > i have an
> > href which looks like this:
> > <td class="all">
> >     <a class="btn" name="D1" href="http://www.cnn.com">
> >         </a>
> > here is my code
> > for incident in row('td', {'class':'all'}):
> >                 n = incident.findNextSibling('a', {'class': 'btn'})
> >                 link = incident.findNextSibling['href'] + "','"
> > any idea what i'm doing wrong here with the syntax?  thanks in advance
>
> It's not the syntax, it's the logic. the a element is not a sibling of
> the td element, it's a child. findNextSibling is going to return the
> next td, assuming there is one. Trying to index
> incident.findNextSibling in the next line is also broken. That's a
> method, not an indexable object. So that line will also break.
>
>         <mike
> --
> Mike Meyer <mwm at mired.org>			http://www.mired.org/home/mwm/
> Independent WWW/Perforce/FreeBSD/Unix consultant, email for more information.