is there a better way?

[Tim Chase]

> You have a list of unknown length, such as this: list =
> [X,X,X,O,O,O,O].  You want to extract all and only the X's.  You know
> the X's are all up front and you know that the item after the last X is
> an O, or that the list ends with an X.  There are never O's between
> X's.
> 
> I have been using something like this:
> _____________________
> 
> while list[0] != O:
>     storage.append(list[0])
>     list.pop(0)
>     if len(list) == 0:
>         break
> _____________________

While it doesn't modify your list, you can try something like

	storage = [q for q in myList if q != O]

If you've already got stuff in storage that you want to keep, you 
can use

	storage.extend([q for q in myList if q != O])

I suppose, if you wanted to remove all the O's, you could then 
just do

	myList = [q for q in myList if q == O]

(trickiness using Oh's vs. using zeros...)

-tkc