sort one list using the values from another list

[Ron Adam]

bearophileHUGS at lycos.com wrote:
> Following Ron Adam solution (and using [] instead of list() in the last
> line), this may be a possible solution of the problem, that is often
> quite fast:
> 
> def psort16(s1, s2):
>     try:
>         d = dict(izip(s2, s1))
>     except TypeError:
>         _indices = range(len(s1))
>         _indices.sort(key=s2.__getitem__)
>         s1[:] = map(s1.__getitem__, _indices)
>     else:
>         if len(d) == len(s1):
>             s1[:] = [d[v] for v in sorted(d)]
>         else:
>             _indices = range(len(s1))
>             _indices.sort(key=s2.__getitem__)
>             s1[:] = map(s1.__getitem__, _indices)
> 
> Bye,
> bearophile

Looks good, but I think It would be simpler to just do.

def psort17(s1, s2):
     try:
         d = dict(izip(s2, s1))
         assert len(d) != len(s2)
         s1[:] = [d[v] for v in sorted(d)]
     except Exception:
         _indices = range(len(s1))
         _indices.sort(key=s2.__getitem__)
         s1[:] = map(s1.__getitem__, _indices)

We don't need to specify which exception.  Any problems will just get 
raised again on the second try it also fails.

Cheers,
    Ron