Avoiding "invalid literal for int()" exception

[John Machin]

aine_canby at yahoo.com wrote:
> >>> v = raw_input("Enter: ")
> Enter: kjjkj
> >>> int(v)
> Traceback (most recent call last):
>   File "<stdin>", line 1, in <module>
> ValueError: invalid literal for int() with base 10: 'kjjkj'
>
> In my program I need to be able to enter char strings or int strings on
> the command line. Then I use an if-elif structure to establish which is
> which. For example -
>
> if uniList[0].lower() in ("e","exit"): # uniList stores a unicode
> string origionally taken from stdin
> 	return
> elif uniList[0].lower() in ("h","help"):
> 	verb.PrintVerb()
> elif uniList[0].lower() in ("p","pass"):
> 	break
> elif int(uniList[0]) in range(0,10):
>         verb.SetImportance(int(uniList[0]))
>         break
> else:
>         verb.AddNewVerb((uniList[0])
>
> How could I avoid the ValueError exception if uniList[0] == "Åker"? I
> was thinking of having something like -
>
> formatError = False
> try:
>       iVal = int(uniList[0])
>       if iVal not in range range(0,10):
>             formatError = True
> catch ValueError:

Perhaps you meant
    except ValueError:
:-)


>       iVal = -1
>

Consider using uniList[0].isdigit() -- see
http://docs.python.org/lib/string-methods.html

HTH,
John