getting a process's PID

[eldorado]

On Wed, 27 Dec 2006, Erik Johnson wrote:

> "eldorado" <eldorado at io.com> wrote in message
> news:20061227102939.L20663 at eris.io.com...
>> Hello,
>>
>> I am trying to get python to give me the PID of a process (in this case
>> HUB).  I have it working, except for the fact that the output includes
>> \012 (newline).  Is there a way to ask python not to give me a newline?
>>
>> Python 1.4 (Oct 14 1997) [C]
>> Copyright 1991-1995 Stichting Mathematisch Centrum, Amsterdam
>>>>> import os
>>>>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'")
>>>>> h = g.readlines()
>>>>> g.close()
>>>>> h
>> ['87334\012']
>
>
> There's more than one way to do it! (Oh, sorry, that's Perl...)
>
> The two most standard ways would be to call strip() on your string to get
> one sans both leading and trialing whitespace
>
>    print h.strip()
>
> or if you know exactly what you've got (i.e., the newline you don't want is
> just the last character), you can just get rid of it:
>
>    h = h[:-1]
>

Thanks for the help, however it doesnt look like those two solutions quite 
work:



>>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'")
>>> h = g.readlines()
>>> g.close()
>>> h
['87334\012']
>>> h = h[:-1]
>>> h
[]
>>>


>>> import string
>>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'")
>>> h = g.readlines()
>>> g.close()
>>> print h.strip()
   File "<stdin>", line 1
     print h.strip()
      ^
SyntaxError: invalid syntax

I looked up the syntax for print and it looks correct (at least to me ;)


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