Question on regex

[Prabhu Gurumurthy]

Hello all -

I have a file which has IP address and subnet number and I use regex to extract 
the IP separately from subnet.

pattern used for IP: \d{1,3}(\.\d{1,3}){3}
pattern used for subnet:((\d{1,3})|(\d{1,3}(\.\d{1,3}){1,3}))/(\d{1,2})

so I have list of ip/subnets strewn around like this

10.200.0.34
10.200.4.5
10.178.9.45
10.200/22
10.178/16
10.100.4.64/26,
10.150.100.0/28
10/8

with that above examples:
ip regex pattern works for all IP address
subnet regex pattern works for all subnets

problem now is ip pattern also matches the last 2 subnet numbers, because it 
falls under ip regex.

to fix this problem, i used negative lookahead with ip pattern:
so the ip pattern now changes to:
\d{1,3}(\.\d{1,3}){3}(?!/\d+)

now the problem is  10.150.100.0 works fine, 10.100.4.64 subnet gets matched 
with ip pattern with the following result:

10.100.4.6

Is there a workaround for this or what should change in ip regex pattern.

python script:
#!/usr/bin/env python

import re, sys

fh = 0
try:
    fh = open(sys.argv[1], "r")
except IOError, message:
    print "cannot open file: %s" %message
else:

    for lines in fh.readlines():
       lines = lines.strip()

       pattIp = re.compile("(\d{1,3}(\.\d{1,3}){3})(?!/\d+)")
       pattNet = re.compile("((\d{1,3})|(\d{1,3}(\.\d{1,3}){1,3}))/(\d{1,2})")

       match = pattIp.search(lines)
       if match is not None:
          print "ipmatch: %s" %match.groups()[0]

       match = pattNet.search(lines)
       if match is not None:
          print "subnet: %s" %match.groups()[0]

fh.close()

output with that above ip/subnet in a file

ipmatch: 10.200.0.34
ipmatch: 10.200.4.5
ipmatch: 10.178.9.45
subnet: 10.200
subnet: 10.178
ipmatch: 10.100.4.6
subnet: 10.100.4.64
subnet: 10.150.100.0
subnet: 10

TIA
Prabhu
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