Printing n elements per line in a list

[Simon Forman]

John Machin wrote:
> Steven D'Aprano wrote:
> > I think it's possible to
> > > hack it up using while loops and some ugly slicing, but hopefully I'm
> > > missing something
> >
> > I don't see why you think that's an ugly hack.
> >
> > def printitems(sequence, count=5):
> >     """Print count items of sequence per line."""
> >     numrows = len(sequence)//count
> >     if len(sequence)%count != 0: numrows += 1
> >     for start in range(0, numrows):
> >         items = sequence[start*count:(start+1)*count]
> >         for item in items:
> >             print item,
> >         print
>
> Ugliness is in the eye of the beholder.
> It is more blessed to add than to multiply.
> Gaze upon this alternative:
>
> def printitems2(sequence, count=5):
>     """Print count items of sequence per line."""
>     for pos in range(0, len(sequence), count):
>         for item in sequence[pos:pos+count]:
>             print item,
>         print
> 
> Cheers,
> John

Very nice.

~Simon