iterator wrapper

[Paul Rubin]

alf <ask at me> writes:
> > |>> I = ([n] for n in i)
> 
> This is nice but I am iterating thru hude objects (like MBs) so you know ...

I don't understand the objection-- the above is entirely correct and
produces the same iterator you'd get from

    def wrap(i):
       for x in i:
           yield [x]
    I = wrap(i)

You could also use
 
   import itertools
   I = itertools.imap(lambda x: [x], i)

which again does the same thing.