Printing n elements per line in a list

[johnzenger at gmail.com]

def perline(n):
    count = 1
    while 1:
        yield (count == n) and "\n" or " "
        count = count % n + 1

r = range(1,101)
p = perline(5)

print "".join("%d%s" % (x, p.next()) for x in r)

unexpected wrote:
> If have a list from 1 to 100, what's the easiest, most elegant way to
> print them out, so that there are only n elements per line.
>
> So if n=5, the printed list would look like:
>
> 1 2 3 4 5
> 6 7 8 9 10
> 11 12 13 14 15
> etc.
>
> My search through the previous posts yields methods to print all the
> values of the list on a single line, but that's not what I want. I feel
> like there is an easy, pretty way to do this. I think it's possible to
> hack it up using while loops and some ugly slicing, but hopefully I'm
> missing something