What's the cleanest way to compare 2 dictionary?

[John Henry]

Thank you.  That works.


Marc 'BlackJack' Rintsch wrote:
> In <1155318148.342951.12590 at h48g2000cwc.googlegroups.com>, John Henry
> wrote:
>
> > When I do it under 2.3, I get:
> >
> >     common_eq = set(k for k in _common if a[k] == b[k])
> >                                    ^
> > SyntaxError: invalid syntax
> >
> > Don't know why that is.
>
> There are no generator expressions in 2.3.  Turn it into a list
> comprehension::
>
>   common_eq = set([k for k in _common if a[k] == b[k]])
> 
> Ciao,
> 	Marc 'BlackJack' Rintsch