how to make a generator use the last yielded value when it regains control

[John Salerno]

John Salerno wrote:
> 2. just make it a function that takes a second argument, that being the 
> number of times you want it to repeat itself and create numbers in the 
> sequence

Here's what I've come up with so far. Probably not the most elegant 
solution because of the nested function, but it does work! :)

def morris(seed, limit):
     num = seed
     numberSet = []

     def nextNum(num):
         num = list(str(num))
         grouping = []
         nextNum = []
         for i in range(len(num)):
             try:
                 if num[i] == num[i + 1]:
                     grouping.append(num[i])
                 else:
                     grouping.append(num[i])
                     nextNum.append(str(len(grouping)) + num[i])
                     grouping = []
             except IndexError:
                 grouping.append(num[i])
                 nextNum.append(str(len(grouping)) + num[i])
                 return ''.join(nextNum)

     for x in range(limit):
         numberSet.append(int(num))
         num = nextNum(num)

     return numberSet