"PAolo" <paolopantaleo at gmail.com> wrote in message
news:1145737240.221433.176160 at i40g2000cwc.googlegroups.com...
> for i in range(1,10):
> if i%2:
> odd.append(i)
> else:
> even.append(i)
In 2.5 you'll be able to say
for i in range(1,10):
(odd if i%2 else even).append(i)
Whether you want to do this is another question entirely, of course.