Object default value

[James Stroud]

I think you want to overload the assignment operator here. I'm not sure that 
is allowed in python (I've never seen it done). You can overload the 
equality, lt, gt, le, ge operators (==, <, ...) such that

class Thing:
  x = 5
  def __str__(self):
    return str(self.x)
  def __eq__(self, other):
      if hasattr(other, 'x'):
          return self.x == other.x
      else:
        return self.x == other

py> athing = Thing()
py> athing.x
5
py> bob = athing.x
py> athing == bob  # having overlaoded equality for athing
True
py> athing is bob  # not the same object
False

But I don't think assignment overloading is allowed in python:

py> athing = Thing()
py> print athing  # having overloaded __str__()
5
py> bob = athing
py> type(bob)     # will not be an int ==> python language constraint
<type 'instance'>

James

On Tuesday 20 September 2005 13:05, ago wrote:
> The print statement was only for illustrative purposes, when calling
> varx=myobj I need to receive obj.x as opposed to the instance of obj,
> but I also need to call vary=myobj.y. Something like that exists for
> com objects/VB, for instance an excel range object uses value as the
> default attribute, so that you can write
>
> set rng=range(...);
> x=rng
> y=rng.value
> 'x==y
> z=rng.attributeXYZ

-- 
James Stroud
UCLA-DOE Institute for Genomics and Proteomics
Box 951570
Los Angeles, CA 90095

http://www.jamesstroud.com/