My First Python Script

[Ed Hotchkiss]

Someone else actually got me some help, the end result he hooked me up with 
was:
  
# function to evaluate all possible IPs

def findIPs():

ipFile = open("IPList.txt", 'w')

for octet1 in range(256):

for octet2 in range(256):

for octet3 in range(256):

for octet4 in range(256):

ipAddress = '%03.d.%03.d.%03.d.%03.d\n' % (octet1, octet2,octet3, octet4)

ipFile.write(ipAddress)

ipFile.close()

 # execute the function

findIPs()


Thanks though, your response helps me understand variables better now..
 On 9/16/05, John Hazen <john at hazen.net> wrote: 
> 
> * Ed Hotchkiss <edhotchkiss at gmail.com> [2005-09-15 20:36]:
> > But then I still get the error with the len(x) statement .. hmm
> 
> Ahh. In the future, it will help us help you, if you make it clear that
> there was an error, and *paste the exact error* into your mail.
> 
> For example, I'm guessing the error you got is:
> 
> >>> len(255)
> Traceback (most recent call last):
> File "<stdin>", line 1, in ?
> TypeError: len() of unsized object
> 
> 
> As Robert said, this is because integers don't have a length.
> 
> James' suggestion to use string formatting is probably the "best"
> solution, but the formatting codes are fairly daunting for someone never
> exposed to them.
> 
> > if len(x) == 1:
> > mySet = '00' + str(x)
> > elif len(x) == 2:
> > mySet = '0' + str(x)
> 
> You know intuitively that strings *do* have length, and you appear to
> know how to create a string from an integer. So the easiest
> modification to your code to make it work wolud be something like:
> 
> mySet = str(x)
> if len(mySet) == 1:
> mySet = '00' + mySet
> elif len(mySet) == 2:
> mySet = '0' + mySet
> 
> Now, this can be made a little more elegant (and generalized) by using
> the algorithm "if the string is too short, keep prepending zeros until
> it's long enough."
> 
> target_length = 3
> mySet = str(x)
> while len(mySet) < target_length:
> mySet = '0' + mySet
> 
> But this isn't as efficient as your solution. Once you know about the
> interesting ability to multiply strings ("0" * 3 = "000"), you can
> create a solution that's general, elegant, and efficient:
> 
> target_length = 3
> mySet = str(x)
> mySet = '0' * (target_length - len(mySet)) + mySet
> 
> HTH-
> 
> John
> 



-- 
edward hotchkiss
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