do cc list from smtplib

[Steve Holden]

Tim Williams (gmail) wrote:
> On 21 Oct 2005 02:34:40 -0700, eight02645999 at yahoo.com
> <eight02645999 at yahoo.com>
> 
>>def email(HOST,FROM,TO,CC,SUBJECT,BODY):
>>    import smtplib
>>    import string, sys
> 
> 
>>    body = string.join((
>>    "From: %s" % FROM,
>>    "To: %s" % TO,
>>    "CC: %s % CC,
>>    "Subject: %s" % SUBJECT,
>>    "",
>>    BODY), "\r\n")
>>
>>    print body
>>
>>    server = smtplib.SMTP(HOST)
>>    server.sendmail(FROM, [TO]+[CC],body)
>>    server.quit()

Assuming that TO and CC are single addresses it would be saner to use:

     server.sendmail(FROM, [TO, CC], body)

- in other words, use a two-element list rather than creating it by 
concatenating two one-element lists!

Note that as far as the SMTP protocol is concerned it's the list of 
recipients that gets actions, not the headers in the message.

stating-the-obvious-ly y'rs  - steve
-- 
Steve Holden       +44 150 684 7255  +1 800 494 3119
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