sort problem

[Kent Johnson]

Michele Petrazzo wrote:
> Lasse Vågsæther Karlsen wrote:
> 
>> How about:
>>
>> list.sort(key=lambda x: x[3])

Better to use key=operator.itemgetter(3)

> Yes, on my linux-test-box it work, but I my developer pc I don't have
> the 2.4 yet. I think that this is a good reason for update :)

or learn about decorate-sort-undecorate:

lst = [ ...whatever ]
lst = [ x[3], i, x for i, x in enumerate(lst) ]
lst.sort()
lst = [ x for _, _, x in lst ]

Kent

> 
> Thanks,
> Michele