struct.unpack

[Fredrik Lundh]

"g.franzkowiak" wrote:

> I've read a pipe and store it in a object.
> My next step was the separation from 4 bytes with
> obj = string.join(list(dataObject)[:4] ==> '\x16 \x00 \x00 \x00'
> and the converting  by
> value = struct.unpack('I', obj) generated the error
> "unpack str size does not match format"
>
> Unfortunately is len(obj) 7, but integer lengt 4.
> Why 7 ?

because string.join inserts a space between the bytes, by default (as
your example shows)

if you really need that join(list) thing (it's not clear how you read it, but
I find it a bit hard to believe that you've managed to read it into some-
thing that's supported by list but not unpack), you can do

    obj = string.join(list(dataObject)[:4], "")

or

    obj = "".join(list(dataObject[:4]))

or some variation thereof.

</F>