Addressing the last element of a list

[Antoon Pardon]

Op 2005-11-14, Paul Rubin schreef <http>:
> Antoon Pardon <apardon at forel.vub.ac.be> writes:
>> We could then have something like the following.
>> 
>> a = 5
>> b = a
>> a @= 7
>> b ==> would result in 7.
>
> Ouch!  :-(((
>
> Can't you live with
>
> a = [5]
> b = a
> a[0] = 7
>
> so b[0] is now 7.

And what do I have to do, in case of the following:

a = [3, 5]
b = a[0]
b @= 7
a ==> would result in [7, 5]

This may seem contrived, but in combination with
parameters it could be usefull.

Something like:

a = [3, 5]

def treat(b):
  lots of code
  b @= new_value

f(a[0])
a ==> would result in [7, 5]

-- 
Antoon Pardon