Sorting x lists based on one list ... maybe an example would make sense:

[Steven Bethard]

Ron Adam wrote:
> You can sort your grades list however you want. If you want to sort by 
> student name instead of student_id, you would use:
> 
>     # Sort grades list by student name.
>     grades.sort(lambda x,y: cmp(students[x[1]][0], students[y[1]][0]))
> 
> Assuming the name is in the first field in the student dictionary-value 
> tuple.  There are probably other ways to do this that are more readable 
> or faster.

Assuming that students[x[1]][0] is what you want to sort on, this may 
also be written as:

     grades.sort(key=lambda x: students[x[1]][0])

It will probably be somewhat faster, but depending on the size of your 
data, you may not notice.

STeVe