line-by-line output from a subprocess
Simon Percivall
percivall at gmail.com
Mon May 23 16:22:04 EDT 2005
Okay, so the reason what you're trying to do doesn't work is that the
readahead buffer used by the file iterator is 8192 bytes, which clearly
might be too much. It also might be because the output from the
application you're running is buffered, so you might have to do
something about that as well.
Anyway, if the output from the child application is unbuffered, writing
a generator like this would work:
def iterread(fobj):
stdout = fobj.stdout.read(1) # or what you like
data = ""
while stdout:
data += stdout
while "\n" in data:
line, data = data.split("\n", 1)
yield line
stdout = fobj.stdout.read(1)
if data:
yield data,
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