count files in a directory

[rbt]

Heiko Wundram wrote:
> Am Samstag, 21. Mai 2005 06:25 schrieb James Stroud:
> 
>>This will work for your purposes (and seems pretty fast compared to the
>>alternative):
>>
>>file_count = len(os.walk(valid_path).next()[2])
> 
> 
> But will only work when you're just scanning a single directory with no 
> subdirectories...!
> 
> The alternative (which will work regardless of subdirectories) is something 
> like the following:
> 
> heiko at heiko ~ $ python
> Python 2.4 (#1, Apr  3 2005, 00:49:51)
> [GCC 3.4.3-20050110 (Gentoo Linux 3.4.3.20050110-r1, ssp-3.4.3.20050110-0, 
> pie- on linux2
> Type "help", "copyright", "credits" or "license" for more information.
> 
>>>>import os
>>>>path = "/home/heiko"
>>>>file_count = sum((len(f) for _, _, f in os.walk(path)))
>>>>file_count
> 
> 55579
> 
> 
> HTH!
> 

Thanks! that works great... is there any significance to the underscores that you 
used? I've always used root, dirs, files when using os.walk() do the underscores make 
it faster... or more efficient?