Reference to self not passed to member function

[Fredrik Lundh]

James Stroud wrote:

> I did this:
>
> py> class bob(object):
> ...   def __init__(self,**kwargs):
> ...     for fname,func in kwargs.items():
> ...       setattr(self, fname, lambda *args : func(*args))
> ...
> py> def doit():
> ...   print "wuzzup?"
> ...
> py> abob = bob(doit=doit)
> py>
> py> abob.doit()
> wuzzup?
>
> Much to my surprise, this works fine.

why is that surprising?  "doit" is a callable, you wrap it in another
callable, and then you store it in an attribute.

that's no different from storing a integer as an attribute, and it
sure doesn't turn your callable into an instance method.

> 1. What exactly is going on?

see above.

> 2. How can I get ref to self passed to doit() if I want it to?

try using this bob instead:

    import new

    class bob(object):
        def __init__(self, **kwargs):
            for fname, func in kwargs.items():
                setattr(self, fname, new.instancemethod(func, self, bob))

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