Faster way to do this...

[Will McGugan]

Harlin Seritt wrote:
> I've got the following code:
> 
> nums = range(0)
> for a in range(100):
>    nums.append(a)
> 
> Is there a better way to have num initialized to a list of 100
> consecutive int values?
> 

Isn't that equivalent to simply..

nums= range(100)

Will McGugan