Knowing the signature of a function

[Xavier Décoret]

Kent Johnson a écrit :
> Xavier Décoret wrote:
> 
>> Hello,
>>
>> I have the following code:
>>
>> def foo(x,y):
>>     pass
>>
>> How can I query the function object foo to know the number of 
>> parameters it expects.  I can find it is a function using callable(f), 
>> I can find some information (listed by dir(foo)) such as the name of 
>> the function,etc.. but nowhere I can find the number of arguments.
>>
>> I would like to know wether the function expects one or zero arguments.
> 
> 
> foo.func_code.co_argcount gives the count of named args. 
> len(foo.func_code.co_varnames) gives the total number of arguments 
> including *args and **kwds args. inspect.getargspec() might also be 
> helpful.
> 
> Kent

Thanks.

Now I have the following issue: what if foo is not a function but a 
callable? inspect.getargspec raises an exception.

I have to do something like:


import inspect

def countargs(f):
     if callable(f):
         if inspect.isfunction(f): return len(inspect.getargspec(f)[0])
         return len(inspect.getargspec(f.__call__)[0])-1
     raise ValueError

class foo:
     def __call__(self,a,b):
         pass

def bar(x):
     pass


print countargs(foo)
print countargs(bar)



Is there any better way?