Creating file of size x

[Andrew Dalke]

Jan Danielsson wrote:
>    Is there any way to create a file with a specified size?

Besides the simple

def make_empty_file(filename, size):
  f = open(filename, "wb")
  f.write("\0" * size)
  f.close()

?

If the file is large, try (after testing and fixing any
bugs):

def make_empty_file(filename, size, block = 32*1024):
  f = open(filename, "wb")
  written = 0
  s = "\0" * block
  for i in range(size//block):
    f.write(s)
  remainder = size%block
  f.write(s[:remainder])
  f.close()

As Grant Edwards pointed out, you can do a seek(size-1)
but I don't know if it's fully portable.

				Andrew
				dalke at dalkescientific.com