how to get name of function from within function?

[Christopher J. Bottaro]

Steven Bethard wrote:

> Christopher J. Bottaro wrote:
>> I want to get the name of the function from within the function. 
>> Something like:
>> 
>> def myFunc():
>>   print __myname__
>> 
>>>>> myFunc()
>> 'myFunc'
> 
> There's not a really good way to do this.  Can you give some more detail
> on what exactly you're trying to do here?

I want to make wrappers around functions but I can't use __getattr__ because
the functions are being published as a SOAP service and the SOAP lib I'm
using requires a callable object as the argument to the publishing
function.

Basically I want to wrap every function in try/except automatically. 
Typically, I suppose people would do that with __getattr__.  The way my
code is now is that every function (err, method) is enclosed in the exact
same try/except error handling code.  Everytime I make a new function, I
copy/paste that try/catch block.  Its ugly, it clutters the code, its prone
to error, and if i decide to change the error handling code later, I have
to change tons of functions.

Actually, I just realized that function call arguments are not passed to
__getattr__, so my idea of wrapping function calls that way won't work.

Is there something like PHP's __call() method in Python?

>> Also, is there a way to turn normal positional args into a tuple without
>> using *?  Like this:
>> 
>> def f(a, b, c):
>>   print get_args_as_tuple()
>> 
>>>>>f(1, 2, 3)
>> 
>> (1, 2, 3)
> 
> Um...
> 
> py> def f(a, b, c):
> ...     print (a, b, c)
> ...
> py> f(1, 2, 3)
> (1, 2, 3)
> 
> ?

In your method, if the name and/or number of positional arguments changes,
the body of the function must change.  I want to avoid that.

Thanks.