Newbie question: how to keep a socket listening?

[Grant Edwards]

On 2005-06-25, Peter Hansen <peter at engcorp.com> wrote:

> You *may* correct, mainly because the OP's code doesn't appear
> to spawn off new threads to handle the client connections,
> which means he can handle only one connection at a time.
> Specifically, while he is talking to one client he is not also
> in an accept() call on the server socket, which means there
> will be (because of the listen(1) call) only a single pending
> connection allowed in the backlog.

But when he closes that connection, he calls accept again. And
it's at that point where he tries to connect and can't. I
think.  

Can the program be pared down to something smaller that
demonstrates the problem?

> I haven't attempted a thorough analysis... just this much,
> trying to see whether it is obvious that the listen(1) is at
> fault -- and it's not obvious.  I thought this response might
> clarify the meaning of listen(1) a little bit for some folks
> nevertheless.

He could change the 1 to a larger number and see if the
behavior changes.

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