A replacement for lambda

[Reinhold Birkenfeld]

Stefan Rank wrote:
> on 30.07.2005 10:20 Paolino said the following:
>> why (x**2 with(x))<(x**3 with(x)) is not taken in consideration?
>> 
>> If 'with' must be there (and substitue 'lambda:') then at least the 
>> syntax is clear.IMO Ruby syntax is also clear.
>> 
> 
> I am sorry if this has already been proposed (I am sure it has).
> 
> Why not substitue python-lambdas with degenerated generator expressions::
> 
>    (lambda x: func(x)) == (func(x) for x)
> 
> i.e. a one time callable generator expression (missing the `in` part). 
> The arguments get passed into the generator, I am sure that can be 
> combined with the PEP about passing args and Exceptions into a generator.

It's hard to spot, and it's too different to a genexp to have such a similar
syntax.

Reinhold