On Fri, 01 Jul 2005 12:24:44 -0700, Devan L wrote: > With the exception of reduce(lambda x,y:x*y, sequence), reduce can be > replaced with sum, and Guido wants to add a product function. How do you replace: reduce(lambda x,y: x*y-1/y, sequence) with sum? Inquiring minds want to know. -- Steven.