string.atoi and string.atol broken?

[Peter Otten]

Mike Moum wrote:

> s.atoi('4',3) should result in 11
> 
> s.atoi('13',4) should result in 31
> 
> s.atoi('12',4) should result in 30
> 
> s.atoi('8',4) is legitimate, but it generates an error.
> 
> Is this a bug, or am I missing something obvious?

You and atoi() seem to disagree about the direction of the conversion, and
atoi() wins :-). It converts a string representation of a number into the
corresponding integer. The second parameter specifies in what base this
string is given. 
You seem to want something like

import string

def itoa(n, base):
     assert 2 <= base <= 16
     if n < 0:
             digits = ["-"]
             n = -n
     else:
             digits = []
     while n:
             n, m = divmod(n, base)
             digits.append(string.hexdigits[m])
     digits.reverse()
     return "".join(digits)

if __name__ == "__main__":
    assert itoa(4, 3) == "11"
    assert itoa(13, 4) == "31"
    assert itoa(12, 4) == "30"
    assert itoa(8, 4) == "20"


Peter