Loop in list.
Stephen Thorne
stephen.thorne at gmail.com
Tue Feb 8 16:07:55 EST 2005
On Tue, 08 Feb 2005 23:07:09 -0500, Caleb Hattingh <caleb1 at telkomsa.net> wrote:
> '>>> a = [i*2*b for i in range(3) for b in range(4)]
> '>>> a
> [0, 0, 0, 0, 0, 2, 4, 6, 0, 4, 8, 12]
>
> Might take you a while to correlate the answer with the loop, but you
> should be able to see after a while that this nesting is the same as
>
> '>>> a = []
> '>>> for b in range(4):
> '>>> for i in range(3):
> '>>> a.append(i*2*b)
There is a subtle error in this explanation. The equivilence actually
looks like:
'> a = []
'> l1 = range(4)
'> l2 = range(3)
'> for b in l1:
'> for i in l2:
'> a.append(i*2*b)
Stephen
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