problem with tk and pass by refference (I think :)

[Diez B. Roggisch]

> I tried it but I got a syntax error. The interpreter didn't like the
> equals sign in the lambda. I am using python 2.3.4. Is there another way
> of writing that?

Strange. This script works and shows the desired behaviour - python is also
2.3.4:

def foo(x):
    print x


fs = [lambda: foo(i) for i in xrange(5)]
for f in fs:
    f()

fs = [lambda x=i: foo(x) for i in xrange(5)]
for f in fs:
    f()


-- 
Regards,

Diez B. Roggisch