On eval and its substitution of globals

[Paddy]

I have had no reply so on revisiting this I thought I would re-submit
it  and point out that there is a question way down at the end :-)

Thanks.

===== Original Post =====
Hi,
I got tripped up on the way eval works with respect to modules and
so wrote a test.

It seems that a function carries around knowledge of the globals()
present
when it was defined. (The .func_globals attribute)?

When evaluated using eval(...) the embedded globals can be overridden
with
the one passed through the eval(...) call

If however you create a new function that calls the first then eval's
global argument is only substituted in the outer call!

TEST:
=====

Python 2.4 (#2, Jan  8 2005, 20:18:03)
[GCC 3.3.5 (Debian 1:3.3.5-5)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> globals().has_key('A')
False
>>> globals().has_key('B')
False
>>> def f1(): return A < B
...
>>> def z(): return f1()
...
>>> eval(f1.func_code,dict(A=1,B=2))
True
>>> eval(z.func_code,dict(A=1,B=2, f1=f1))

Traceback (most recent call last):
  File "<stdin>", line 1, in ?
  File "<stdin>", line 1, in z
  File "<stdin>", line 1, in f1
NameError: global name 'A' is not defined


ENDTEST
=======

Is there a way to do a deep substitution of the globals?

I should add that f1 is given as-is. I can modify z,
and f1 is just one of many functions given and function z
is some boolean function of the f<n>'s

Thanks, Pad.