[PATCH] Re: frozenset() without arguments should return a singleton

[Jp Calderone]

On Sat, 12 Feb 2005 23:21:58 +0100, Stefan Behnel <stefan.behnel-n05pam at web.de> wrote:
>
> 
> Raymond Hettinger wrote:
>  >Stefan Behnel wrote:
> >>I stumbled over the fact that 'frozenset()' doesn't return a constant but
> >>creates a new object everytime. Since it is immutable, I wrote to  c.l.py 
> >>that this behaviour is different from what tuple() & Co do.
> > 
> > It is not quite correct to say that this is what all immutables do:
> > 
> > 
> >.>>>x = 500
> >.>>>y = 600 - 100
> >.>>>x is y
> > False
> 
> I know. The same is true for concateneted strings, etc. But whenever an 
> immutable object is created directly ('by hand'), it holds. It also holds, 
> btw, for tuple() - as opposed to ().
> 

    $ python
    Python 2.3.5c1 (#2, Feb  4 2005, 10:10:56) 
    [GCC 3.3.5 (Debian 1:3.3.5-8)] on linux2
    Type "help", "copyright", "credits" or "license" for more information.
    >>> long() is long()
    False
    >>> 

  Jp