"Collapsing" a list into a list of changes
Tony
aclarke11 at yahoo.co.uk
Sat Feb 5 07:36:12 EST 2005
Alan McIntyre wrote:
> Hi all,
>
> I have a list of items that has contiguous repetitions of values, but
> the number and location of the repetitions is not important, so I
just
> need to strip them out. For example, if my original list is
> [0,0,1,1,1,2,2,3,3,3,2,2,2,4,4,4,5], I want to end up with
[0,1,2,3,2,4,5].
>
> Here is the way I'm doing this now:
>
> def straightforward_collapse(myList):
> collapsed = [myList[0]]
> for n in myList[1:]:
> if n != collapsed[-1]:
> collapsed.append(n)
>
> return collapsed
>
> Is there an elegant way to do this, or should I just stick with the
code
> above?
>
> Thanks,
> Alan McIntyre
> http://www.esrgtech.com
Here is a version using dictionary properties, ie no duplication of
keys.
def condense(l):
d={}
for item in l:
d[item]=1
l=d.keys()
return l
Cheers
Tony
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